Construction of Triangle using SAS Criteria
Construction of Triangle using SAS Criteria
Construction of Triangle using SAS Criteria: In SAS Triangle construction we need to know the length of two sides and an angle. But the angle should lie between the two sides or we can say should be included between the two sides.
Let us suppose we have to construct a triangle ABC and we know the length of the two sides AB and BC, moreover we know the angle B. If we draw arough sketch we see that angle B is the included angle between the side AB and BC. Hence it satifies the condition for the construction of triangle using SAS Criteria.The steps of construction are as follows:
| Step 1 : Draw a line segment AB of length given to us. |  |
| Step 2 : Using protractor, draw ∠ABK = |  |
| Step 3 : On the line segment BK, using a compass and keeping the pointer at B and radius equal to the length of BC draw an arc and mark the point as C |  |
| Step 4 : Join A and C. ΔABC is the required triangle. |  |
Illustration: Construct a ΔABC, in which ∠B = , AB = 4.8 cm and BC = 5.2 cm.
Before doing construction, draw a rough sketch, so that you will get an idea which side is taken as a base.Here after drawing a rough sketch, we are sure that the base is AB = 4.8 cm.
Step 1 : Draw AB = 4.8 cm.
Step 2 : Using protractor, draw ∠ABK =
Step 3 : On the line segment BK, cut off BC = 5.2 cm.
Step 4 : Join A and C. ΔABC is the required triangle.
In the following figure if AB = AC then find Draw the figure Book name - TALENT & OLYMPIAD 332 page No. 142 Q. no. 18 | |||
| Right Option : B | |||
| View Explanation | |||
If in a | |||
| Right Option : D | |||
| View Explanation | |||
Arrange the following of isosceles triangle PQR in which each of the equal sides is of length 3 cm and the angle between them is
| |||
| Right Option : A | |||
| View Explanation | |||
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